where is the total number of atoms (except hydrogen) present in the ring and is the number of oxygen atoms. For the above crown ether, what is the value of ?
The molecule above is a crown ether. They are named as
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For the above crown ether the total no. of carbon atoms = 1 0 and total no of oxygen atoms = 5 .Hence n = 1 0 + 5 and m = 5 so the name of the compound is 1 5 − c r o w n − 5