Super Naruto and his foe "Pain" are battling on Earth. (Somehow) Pain uses a gravity controlling jutsu to split gravity in half for him to keep up with Naruto's insane sonic speed. Pain has a mass of 62 kg. Naruto overwhelms Pain using his signature rasengan which forces Pain to fly backwards with it's incredible force of 250 N and moves Pain at a velocity of 50 m/s. Based off of this awesome information, how far in meters does Pain travel until he reaches a velocity of 0 m/s? The force is applied as shown in the picture.
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actually naruto was in sennin mode during his fight with pain....f=m*(v^2-u^2)/2as.....=>s=(62times50times50)/2times250.....=>s=310m...
Nice one! I am preparing mine. @Robert Fritz
i think you should use the momentum and impulse formula for this problem
The correct equation would be v=u+at, the equation you wrote is wrong you swapped s(displacement) with t(time)so, its basically v^2=u^2+2as. In both cases the answer is wrong tho ^^
You really had to use Naruto and Pein? Yes, its supposed to be pein
Conversation of Energy:
Step 1: (mxvxv)/2=forcex displacement
Step 2: (62x50x50)/2=250xdisplacement
Step 3: Displacement= 310 meter
Finally someone watches naruto in here !!!!
v^2=u^2+ 2ax---------(i) F=ma-------------------(ii)
we have to find X from (i) and (ii).
i think you are wrong,your question say pain use the jutsu for gravity it means that his weight now is half than before his use the jutsu it menas his mass is half not 62 but 31, my calculating is 155 meter
it said mass, not weight. Weinght = mass x gravity, but mass is nothing to do with the gravity, they are not related
The distance between point A and B is d =AB We know that Initial kinetic energy - Final kinetic energy = Fxd ,Vb=0 ==>Final kinetic energy = 1/2xMxVb²=0 d= (1/2 xMxVa²)/F d=0.5x62x50²/250 d=310meters
i think there is a mistake in the problem description. it was solved with pretty much basic equation: E=(m v^2)/2 and E=F s which when substituted still did not make any sense to the problem in the first place but still giving correct answer.
What's E? The equations I used I thought were pretty accurate though because this question has 31 solvers...... I hope that there not all confused about the answer.
E is the kinetic energy. from what i understand from the problem and picture, the one naruto knocked is flying at 50m/s so E is his kinetinc energy. and he should not have any resistance to the ground. so i assume that if his chi gives 250N braking power, so he actually brakes and with that amount of braking power it tooks him 310m to stop.
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....that's definitely a different approach.
Even if this is your approach how can you assume that naruto has the same mass as pain.I donot think this is an elastic collison.Can you please explain it @Sony Lin @Robert Fritz
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Some of the info was not needed.....heheh. It took me forever to make this problem because of a long time of research on my phone. First, you might have tried to figure out the static coefficient of friction, unfortunately this is not needed, it would be about .8 because 250= x303.8N which is half of gravity times Pains mass. All that needs to be done is use Newtons 2nd law= Force=mass acceleration and figure out how much the object decelerates. 250=62x x=4m/s. Then use an equation I found online ( which is hopefully correct ) v 2=u 2+2at. Final velocity 0= 2500-8m/s. This came out to be 2500m/s/8m/s=312.5 meters. If I'm wrong..... I'm really really sorry. Tell me what to change and if it sounds reasonable I'll try it.