Domain of a Function

Calculus Level 2

Determine the domain of the function f ( x ) = x 2 − 1 x − 1 f(x) = \dfrac{x^2-1}{x-1} .

R ∼ { − 1 } \mathbb R \sim \{ -1 \} R ∼ { 1 , − 1 } \mathbb R \sim \{ 1,-1 \} R ∼ { 1 } \mathbb R \sim \{ 1 \} R \mathbb R

César Emanuel Castro by César Emanuel Castro , 20, Honduras

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1 solution

The only real value not in the domain is 1 1 , where f ( x ) f(x) is of the indeterminate form 0 0 \frac{0}{0} .

Although lim ⁡ x → 0 f ( x ) = 2 \lim_{x \rightarrow 0} f(x)=2 .

f ( − 1 ) = 0 f(-1)=0 is well-defined, so the answer should be B . D f = R − 1 B. D_{f} =R-1

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false, It is not correct the domain of the function is R.

Nzubechi Justice - 11 months, 1 week ago

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how is it so?

César Emanuel Castro - 10 months, 2 weeks ago

The question was what is the domain of the function,and not which value is not in the domain of the function.

Oleg Yovanovich

Oleg Yovanovich - 6 months, 1 week ago

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