Natural numbers
Algebra
Level
pending
If a,b,c and d are natural numbers and if a=bcd, b=cda, c=abc then (a+b+c+d) *(a+b+c+d) is
2
8
16
1
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1 solution
If a,b,c,d all are equal to 1then the a=bcd,b=cda,d=abc so (1+1+1+1)(1+1+1+1)=4*4=16 so answer is 16