nature of e

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what is the natural log of e^7


The answer is 7.

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1 solution

Saurabh Mallik
Aug 30, 2014

The natural logarithm of a number is its logarithm to the base e e .

So, Natural log of e 7 = l o g e e 7 e^{7} = log_{e}e^{7}

Let l o g e e 7 = x log_{e}e^{7}=x which can be written as:

e x = e 7 e^{x}=e^{7}

x = 7 x=7

Thus, the answer is: l o g e e 7 = 7 \boxed{log_{e}e^{7}=7}

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