NBA Maths
In a basketball match each player get a mark based on the amount of baskets, rebounds and foults they score. The top three marks were 27,15 and 8, which were made by the players N, B and A. The player N was rejected because he commits 5 foults, but he got 2 rebounds. The player B was the one who score more points(baskets). The player A didn't commit any foults, nor get any rebounds. Which player get each mark if each point(basket) they score double his value, each rebuond sum one point to the final mark and each foilt substracts one point. Note: Each basket doesn't double the final value, it doubles the value of the baskets. Ex. If a player score one triple(3points basket) their mark would be 6.
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1 solution
B gets a mark of 27 because is the biggest mark and was the whose score was higher. N gets a mark of 15 because he commits five foults and 2 rebounds, so in conclusion he must have an odd mark, whose last digit must be 1,3,5,7,or 9. In this case 5. So the answer is 15 So A gets a mark of 8 because he didn't commit any foult nor any rebound, so the last digit of his mark must end in 0,2,4,6 or 8., like in this case