Near 100 multiplication 2

(94-2)(94+2)= $94^2$ - $2^2$ $\small~~{(a-b)(a+b)=a^2-b^2}$ $=8836-4=\Large 8832$ For calculating $94^2$ decrease 94 by as much as it is less from 100(i.e subtract 6) and then attach to it square of that subtracted number. 1. 96- $4$ =88, 2. $94^2$ =88 $36$

● $100-92=8$ ..... $(1)$
● $100-96=4$ ..... $(2)$

Multiplying $(1)$ and $(2)$ .
Therefore, last two digits $\boxed{32}.$

Now, first two digits $92-4=96-8=\boxed{88}.$

$\therefore 92×96=\boxed{8832}.$

a×b = x

100-(a+b) = y

(100-a)×(100-b) = "x"+"y"

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92×96 = (100-8)×(100-4)

a = 8

b = 4

x = 100-(8+4) = 88

y = 8×4 = 32

92×96 = "x"+"y" = 8832