When the speed of a car is increased by 4 km/h, it takes 4 hour less to cover a distance of 32 km . What was the speed before the increase? (in km/h)
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Let the initial speed of the car be x . Therefore, time taken by car to cover a distance of 3 2 km is x 3 2 .
Now, when speed is increased to x + 4 , time taken is x + 4 3 2 , which is 4 hours less than the initial time.
Therefore the equation becomes x 3 2 − 4 = x + 4 3 2
⟹ 3 2 ( x + 4 ) − 4 x ( x + 4 ) = 3 2 x
⟹ x 2 + 4 x − 3 2 = 0
= ( x + 8 ) ( x − 4 ) = 0
⟹ x = − 8 or x = 4
Since speed cannot be negative, therefore x = 4 .