A geometry problem by Alisina Zayeni

Geometry Level 4

In A B D \triangle ABD , B = 10 0 \angle B=100^\circ and C C is the point on B D BD such that A B = B C AB=BC . If A C = B D AC=BD , find C A D \angle CAD .


The answer is 10.

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1 solution

Alisina Zayeni
Jan 1, 2018

Draw an equilateral triangle ABE on side AB. So the triangles AEC & ABD are congruent. So angle (A) =50 and BAC=BCA=40 . So CAD =10

Wrong I m interrupted

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