Let be non empty subset of real numbers .
P : There is a rational number in such that .
Which of the following is the negation of P ?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Since ( P ) = P , let's say P is the negation of one of the statements. This way is probably easier to find the answer. We can see that the negation of "Every rational number x in S such that x < 0 " is "There is AT LEAST one rational number x in S such that x ≥ 0 ", hence statement P . So, the first statement is the answer.