Since 1 + 2 + 3 + ⋯ < 2 True or false 2 1 + 3 1 + 4 1 + ⋯ < 1
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2 1 + 3 1 + 4 1 + . . . < 1 ⇔ 2 1 + 3 1 + 4 1 + . . . < 1 2 ⇔ 3 1 + 4 1 + . . . < 2 1 ⇔ 3 1 + 4 1 + . . . < 4 1 ⇔ 4 1 + . . . < − 1 2 1 The left-hand-side is positive, which can't be less than a negative number.
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We can easily verify that 2 1 + 3 1 ≈ 1 . 0 4 so ∀ x > 0 , 2 1 + 3 1 + x > 1