What is the smallest a ∈ N , greater than 1 , for which the following equation has a solution x ∈ N ? lo g a ( x lo g a ( x lo g a ( x ⋯ ) ) ) = x
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You mean a = 2 , x = 4 ?
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Thanks. I thought we need to find x . There are actually two cases.
lo g a ( x ⋅ lo g a ( x ⋅ lo g a ( x ⋅ ⋅ ⋅ ) ) ) = x
We can take advantage of the fact that a copy of the outer expression exists inside the expression. The boxed value must be x .
lo g a ( x ⋅ x ) = x lo g a ( x 2 ) = x 2 lo g a ( x ) = x lo g a ( x ) = 2 x
We need to find the smallest natural value for a such that a > 1 . When we try a = 2 , we can use a graphing calculator or a software like Desmos to show that the two graphs cross, and solutions exists. Thus, a = 2 .
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lo g a ( x lo g a ( x lo g a ( x ⋯ ) ) ) lo g a ( x 2 ) a x = x = x = x 2
There are two cases, when x = { 2 4 ⟹ a = 2 ⟹ a = 2 . Therefore a = 2 .