Nested logarithmic equation with a parameter

Algebra Level 2

What is the smallest a N a \in \mathbb{N} , greater than 1 1 , for which the following equation has a solution x N x \in \mathbb{N} ? log a ( x log a ( x log a ( x ) ) ) = x \log_a ( x \log_a ( x \log_a ( x \cdots ) ) ) = x


The answer is 2.

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2 solutions

Chew-Seong Cheong
Jun 19, 2020

log a ( x log a ( x log a ( x ) ) ) = x log a ( x 2 ) = x a x = x 2 \begin{aligned} \log_a(x\log_a(x\log_a(x \cdots))) & = x \\ \log_a(x^2) & = x \\ a^x & = x^2 \end{aligned}

There are two cases, when x = { 2 a = 2 4 a = 2 x = \begin{cases} 2 & \implies a = 2 \\ 4 & \implies a = 2 \end{cases} . Therefore a = 2 a = \boxed 2 .

You mean a = 2 , x = 4 a = 2, \: x = 4 ?

Tomáš Hauser - 11 months, 3 weeks ago

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Thanks. I thought we need to find x x . There are actually two cases.

Chew-Seong Cheong - 11 months, 3 weeks ago
Ved Pradhan
Jun 18, 2020

log a ( x log a ( x log a ( x ) ) ) = x \log_{a}(x \cdot \boxed{\log_{a}(x \cdot \log_{a}(x \cdot \cdot \text{ } \cdot))})=x

We can take advantage of the fact that a copy of the outer expression exists inside the expression. The boxed value must be x x .

log a ( x x ) = x \log_{a}(x \cdot x)=x log a ( x 2 ) = x \log_{a}(x^{2})=x 2 log a ( x ) = x 2\log_{a}(x)=x log a ( x ) = x 2 \log_{a}(x)=\dfrac{x}{2}

We need to find the smallest natural value for a a such that a > 1 a>1 . When we try a = 2 a=2 , we can use a graphing calculator or a software like Desmos to show that the two graphs cross, and solutions exists. Thus, a = 2 \boxed{a=2} .

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