Nested problem

Square both sides of the original equation to obtain:

$\sqrt{\dfrac{1}{x}} =4.$

Then square both sides again:

$\dfrac{1}{x} = 16 \longrightarrow x=\dfrac{1}{16}$

Simply, here is from Koro-sensei, kukukuku

$\large\sqrt{\sqrt{\dfrac{1}{x}}}=2$ $\sqrt{\dfrac{1}{x}}=4$ $\dfrac{1}{x}=16$ $1=16x$ $x=\dfrac{1}{16}$

Follow you? For this piece of nut? Hahaha. No. Btw, just square both sides twice. So simple! I mean, 84% of the people got it right! Whoa.

Square both sides twice..

1/x = 16

x = 1/16

Squaring both sides twice gives $\frac{1}{x} = 16$ .

Then, solving for $x$ gives us the answer of $\frac{1}{16}.$

Simply after squaring both sides twice we get 1/x = 16

X= 1/16 :))

[(1/x)^1/2]^1/2 = 2, Then (1/x)^1/4 = 2; x^-1/4 = 2 ; x^-1 = 2^4 ; 1/x = 2^4 Therefore 1/x = 16, Hence x = 1/16

Logic: only answer it COULD be: had to be an even number

Square both sides to remove the first square root. The equation should now be sqrt(1/x) = 4. Square both sides again, you have 1/x =16. Divide by 16 and multiply by x to make x = 1/16

Just guess and check

1/x = y -> substitute 1/x for y

√√y = 2 y = 2^4 y = 16 -> 1/x must be 16 to satisfy the condition

1/x = 16 16x = 1 x = 1/16 -> for 1/x be 16, x must be 1/16

answer = 1/16

((x^{-1})^{1/2})^{1/2}=2

x^{-1/4}=2

(x^{-1/4})^{-4}=2^{-4}

x=1/2^{4}=1/16

In This Case, You have To Keep Breaking The Square Root And That Means Starting From The Inside Of The Square Root And Work your Way Onto The Outer Square Root To Get 2