3 4 + 2 3 4 + 2 3 4 + 2 3 4 + 2 3 4 + ⋯ = ?
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x = 3 4 + 2 x
x 3 = 4 + 2 x
x 3 − 2 x − 4 = 0
( x − 2 ) ( x 2 + 2 x + 2 ) = 0
x 2 + 2 x + 2 has no solutions (as b 2 − 4 a c = 2 2 − 4 ( 2 ) = − 4 ), so x = 2 is the only solution.
Note that this is actually an iterative formula, which provides a numerical way of solving an equation. Type in a random number on your calculator, and use the "answer" function to substitute it into 3 4 + 2 ( a n s ) . Then repeatedly press = , and the value on the calculator display will converge on 2.
Convergence on the calculator is likely due to the rounding
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x = 3 4 + 2 3 4 + 2 3 4 + 2 3 4 + 2 3 4 + ⋯
x = 3 4 + 2 x
Cubing both sides.
x 3 = 4 + 2 x
x 3 − 2 x − 4 = 0
( x − 2 ) ( x 2 + 2 x + 2 ) = 0
∴ x = 2
⇒ 3 4 + 2 3 4 + 2 3 4 + 2 3 4 + 2 3 4 + ⋯ = 2