Neutralizing HCl Using NaOH
Chemistry
Level
1
How much of 0.50 NaOH is needed to neutralize 25.0 mL of 0.75 M HCl?
16.5 mL
37.5 mL
50.0 mL
150 mL
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1 solution
0.5 x V = 0.75 x 25
V = 0.75 x 25 / 0.5
= 3 x 25 / 2
= 37.5 mL