New Delhi Metro

s = √ ( 400m² + 150²)

s = 427.2 m

t = s / v

t = 427.2m / 2m/s

t = 213.6 s

If we represent this data in a graph, we see that the walking distance from one station to another is the hypotenuse of the triangle so formed with the other 2 sides being 150 m and 400 m. Given speed of person $=2$ m/s

So, required distance $=\sqrt{150^{2}+400^{2}} = \sqrt{22500+160000} = \sqrt{182500} = \boxed{427.20} m$

Now, Time $=\frac{Distance}{Speed} = \frac{427.20}{2} = \boxed{213.60} sec$

Since the polar directions East and North are perpendicular to eachother, the figure formed will be a right angled triangle, with height $400m$ and base $150m$ . Therefore, the distance covered on walking directly from one station to the other is represented by the hypotenuse, that comes out from the Pythagoras Theorem-

$400^2 + 150^2 = H^2$

$H^2 = 18250$

$H = 427.20$

Therefore, the distance is $427.2m$ .

Now, we have to calculate the time. We know that $t = \frac{s}{v}$ , where $t =$ time, $s =$ distance and $v =$ velocity.

Putting the values, we get-

$t = \frac{427.20}{2} = \fbox{213.60}$

According to the problem, we get a right triangle with sides $400$ m and $150$ m each .

We have to find the displacement between the two stations , i.e the hypotenuse of the triangle .

Hence , we find the * hypotenuse * i.e the distance (d) :

$d^2 = (400)^2 + (150)^2$

$d^2 = 160000 + 22500$

$d = \sqrt{182500}$

$d = 427.2$

Now , since :

$speed = \dfrac{distance}{time} \Rightarrow time = \dfrac{distance}{speed}$

Therefor by putting the values :

$\Rightarrow time = \dfrac{distance}{speed} = \dfrac{427.2}{2} = \boxed{213.6} s$

Using Pythagorus' Theorem, we can see that the distance directly between the two places is:

$\sqrt{400^2 + 150^2} = 427.1\dots$

We know that $time = \frac{distance}{speed}$ , so using this value, we find that the time in seconds is:

$\frac{427.1\dots}{2} = \fbox{213.6s}$

We first need to calculate the distance,s, between the 2 stations, for which we use pythagoras theorem. $s = \sqrt{400^{2}+150^{2}} = 427.200$ We know the speed and the distance, so we simply need to calculate the time using distance/speed.

Therefore, time taken = $\frac{s}{2} = 213.6s$

We need to find the distance between the two stations so we will use Pythagorus' theorem. Let point A be the Barakhambha Road station, let 400m north of this beB and let C be the Shivaji Bridge station. Then ABC is a right triangle. We need to find the distance AC=s. s = √ ( 400m² + 150²)

s = 427.2 m

t = s / v

t = 427.2m / 2m/s

t = 213.6 s

Displacement s=427.2001873 m velocity v=2 m/s Time t= displacement/velocity t=427.2001873/2=21306000936

s = √ ( 400m² + 150²)

s = 427.2 m

t = s / v

t = 427.2m / 2m/s

t = 213.6 s

Pythagoras theorem

one station being 400 m and other 150 m , we need to take vector sum we get 427 m this distance we need to travel from one station to other n den dividing it by velocity 2 m/s we get Time= 214

Its applies pythogoras theorem

Lets say the distance be x

x^2=400^2 + 150^2

x^2=182500

x=427.2

So distance- 427.2 m and speed = 2 m/s

T=d/s

Time=427.2/2=213.6 seconds.

Use Pythagoras Theorem to find the exact distance b/w the two points and then calculate the time using Time=Distance/Velocity=213.6 approx. 214

the distance between the shivaji bridge and the Barahkhamba road can be found out by the Pythogras theorem. therefore a triangle has been formed with the base equal to 400 m and the height equal to 150 m.so distance (hypotenuse)= root of(base ^2 +height^2).Here-distance=root(160000+22500) =square root of 182500=427.200(distance) as speed equals distance/ time =>2=427.2/time =>time=427.200/2 =213.600

If I walk between the two stations then i have to walk through a direct path between 2 stations not the metro path......ie D=[(400)^2+(150)^2]^(1/2)=427.2 m So, t=D/v=427.2/2= 213.6 secs

The distance between the 2 stations is 150+400 = 650 m. However, walking directly between the 2 stations represents displacement. Using pythagoras theorem, we find that displacement^2 = 150^2 + 400^2-----> d = sqrt.182500 = 427.200187266. Now, time = distance/speed-------------> 427.200187266/2 = 213.600093633=Answer

actual distance between the two stations= sqrt(400 400+150 150)=427.200 walking speed=2m/s hence time taken in seconds=distance/speed =427.200/2 =213.600

Pythagoras is Elementary School.

A^2 + B^2= C^2, to get a distance of 427.2. Divide by 2 to get 213.6.

Displacement is measure by Pythorgoras Theorem (as 150 m towards East and then 400 towards North ; makes a right angle triangle). When displacement is measured then we simply use the formula; Velocity = Displacement/Time and calculate time .

simple calculate the length of line by (x1-x2)^2+(y1-y2)^2 as a whole under root, and divide it by speed u will get time that 214

s=sqrt(400^2+150^2) s=427.2 m V=2m/s => t=S/V t= 213.6sec

Suppose that the station is the point of origin the Shivaji Bridge is 400 meters to the north and impose this point of (A) and 150 meters to the east and impose this point (B) and draw a straight line up between (A) and (B) we can calculate the distance between these two dots using the theory of Pythagoras triangle-based We get the distance (X) the distance between these two dots by using the relationship [X = V * T] Where (V) Speed we get (T) the time required

Let the resultant distance between the two stations be D

By Pythagoras theorem

(400)^2 + (150)^2=D^2.

Hence D ₌ 50√73 m

From speed ₌ Distance/Time

       Time ₌ Dinstance/Speed

Thus Time ₌ (50√73)/2

Therefore the time in seconds ₌ 213.6 s

The distance between New Delhi station to Shivaji Bridge station is equal $\sqrt {400^2+150^2}=50\sqrt {73}$

Thus the time needed to reach one station from another station if we walk with $2 m/s$ speed is

$\frac {50\sqrt {73}}{2}=213.600$

4oo^2+150^2=427.200^2

427.200/2=213.600

$\\ \left ( \Delta S \right )^2 = \left ( 400 \right )^2 + \left ( 150 \right )^2 \\\\ \left ( \Delta S \right )^2 = 182500 \\\\ \Delta S = 427.2 \; \text{m}$

Por fim,

$\text{S = v} \cdot \text{t} \\\\ 427.2 = 2\text{t} \\\\ \boxed{\text{t = 213.6 s}}$

This is basically the Pythagorean Theory which is a squared plus b squared equals c squared. I did 400 squared plus 150 squared which gave me a number. Then i found the square root of that number and divided that by 2 to get the seconds.

since these two directions are perpendicular to each other hence the distance to be covered if we go directly is \sqrt{400^2+150^2} m. this is obtained using Pythagoras theorem. hence the time taken is distance covered\speed

(Square root (400^2+150^2) )divide by 2