New type of series!

Given that p = p r i m e ( f + g ) ( p ) p s = p = p r i m e ( f g ) ( p ) p s \sum_{p=prime}\dfrac{(f+g)(p)}{p^s}=\sum_{p=prime}\dfrac{(f*g)(p)}{p^s} where f g f* g is a dirichlet convolution then this is always true (assuming both sides converges) if f,g are

multiplicative,additive multiplicative,multiplicative, No restriction required, always true. additive,additive

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