A man drive his car to the office at 20miles/hr. After reaching the office, he realized that its a new year holiday so he went back home at a speed of 30miles/hr.
Discounting the time spent in the stoppage what was his average speed of his journey ?
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Let distance be s First 20=s/t s=20t Second s=30T T=2/3t Total distance=40t Total time=5/3t Therefore v average=24