28,000 people read
NanJing Morning News
,
23,000 people read
NanJing Evening News
, and
4,000 people read both.
How many people read neither?
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solve using sets let p=28,000 q=23,000 p and q = 4000 u=50,000 ; therefore (p and q)'= 50000-{(28000+23000)-4000} = 3000
I have a question How can there be 51,000 people who subscribe to only one of the newspapers in the town if it says that the total population is 50,000?
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If we add the number of people who read the Nanjing morning and Nanjing evening, we would count people who read both TWICE.
So because of that, we need to subtract the sum by 4 0 0 0 people those that read both, resulting in 4 7 0 0 0 .
Surely number of people who read morning = 28000 - 4000 = 24000 number of people who read evening = 23000 - 4000 = 19000 total readers = 43000 total non-readers = 7000
that's a bitttt complicated, sorry.
Brother this question is wrong if totall it it 5000 xtra person auto addedd
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Question is not wrong. Did you notice that there are some people who read both of the papers? That means, 1st paper read by x number of people and 2nd paper read by y number of people and there are some people who read both(and they are from x and y).
Draw a Venn Diagram, then it's so easy.
Let A = 28000,B=23000. A & B common People are 4000, let C = 4000, so total people is total People = (A+B)-C.totalPeople = 51000-4000=47000.
We know that total people in town is 50000 so we have left 3000 to reach total people. So the answer is 3000.
Or you could do it the way I did it....... 28000 people that read the NanJing Morning News + the 23,000 people that read NanJing Evening News = 51000 ( try doing that in your head, really! It's easy!) 51000 - the 4000 that read both = 47000, there are 50000 people in the town, so, it's 50000 - 47000 = 3000, so 3000 read both newspapers! Technically, ours are the same though... But, good explaining! Thx!
Nice answer
From the Venn Diagram above, the number of people who read neither is
5 0 0 0 0 − 1 9 0 0 0 − 4 0 0 0 − 2 4 0 0 0 = 3 0 0 0
That's how I did it! ( explained in great detail above) the only thing I didn't do is the Venn Diagram.
28k + 23k = 51k 51k - 4k = 47k 50k-47k = 3k
:))
People who read the first newspaper = 28000 People who read the second newspaper = 23000 Let people who read first only as 28000-x (in which x is the number of people out of the 28000 who read both) Let people who read second only as 23000-y (in which y is the number of people out of the 23000 who read both) So x+y=4000 By adding both we get the total number of people who read any of the two newspapers: 28000-x+23000-y Since x+y=4000 Therefore x= 4000-y By substituting: 28000-(4000-y)+23000-y 28000-4000+y+23000-y 28000-4000+23000=47000 Since total number of people in the city =50000 Therefore number of people who read neither = 50000-47000=3000
Just subtract 4000 from first and second newspaper readers and let the people who read nothing be x ,
19000 + 24000 + 4000 + x = 50000
=> 47000 + x = 50000
=> x = 3000
50,000-4,000 is the number of people who don't read both news. The total number of people who read at least one type of news is (28,000+23,000)-4000. We subtract 4000 because that gets rid of the people who read both types of news. Now we are left with 47,000, which is the number of people who read either types of news, or both. So the people who read neither will be 50,0000 (total population) - 47,000 (The number of people who read at least one of the magazines.
I attacked this problem by using Venn Diagram.
Apply Inclusion-Exclusion Principle, i.e., 28000+23000-4000=47000. Then subtract 47000 to 50000 to get the number of people who neither read those newspapers.
Thus, the answer is 3000.
50000-(28000+23000-4000)=3000
Since 4000 did read both out of 50,000 ,so 46,000 did not read papers,Now, 22,000 ( 50,000-28,000)and 27,000 ( 50,000-23,000)did not read NanJing morning and Nanjing Evening news. Therefore 22,000 +27,000 =49,000 did not read papers and 49,000 -46,000 =3000 people read neighter Ans. K.K.GARG,India
n(A) = 28000. n(B) = 23000. n(A^B) = 4000 n(AUB) = n(A) + n(B) - n(A^B). n(AUB) = 28000 + 23000 - 4000. n(AUB) = 47000. No. Of people who read neither =Total - n(AUB) . =50000 - 47000 . = 3000.
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Let total people in town be denoted by x . Then x = 5 0 0 0 0 .
People who read newspaper:
Nanjing morning: a + b = 2 8 0 0 0
Nanjing evening b + c = 2 3 0 0 0
People who read both b = 4 0 0 0
People who read neither of them: x − ( a + b + c ) = 3 0 0 0 .