Newspaper mania

In a town of 50,000 people,
28,000 people read NanJing Morning News ,
23,000 people read NanJing Evening News , and
4,000 people read both.

How many people read neither?

3000 2500 1000 4000

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10 solutions

Mahendra Bisht
Jun 6, 2014

Let total people in town be denoted by x x . Then x = 50000 x =50000 .

People who read newspaper:
Nanjing morning: a + b = 28000 a+b =28000
Nanjing evening b + c = 23000 b+c =23000
People who read both b = 4000 b= 4000
People who read neither of them: x ( a + b + c ) = 3000 x-(a+b+c) = \boxed{ 3000} .

solve using sets let p=28,000 q=23,000 p and q = 4000 u=50,000 ; therefore (p and q)'= 50000-{(28000+23000)-4000} = 3000

Kumar Abhijeet - 6 years, 12 months ago

I have a question How can there be 51,000 people who subscribe to only one of the newspapers in the town if it says that the total population is 50,000?

Danny Swartz - 5 years, 3 months ago

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If we add the number of people who read the Nanjing morning and Nanjing evening, we would count people who read both TWICE.

So because of that, we need to subtract the sum by 4000 4000 people those that read both, resulting in 47000 47000 .

Micah Wood - 5 years ago

Surely number of people who read morning = 28000 - 4000 = 24000 number of people who read evening = 23000 - 4000 = 19000 total readers = 43000 total non-readers = 7000

Georges Ajaka - 5 years, 2 months ago

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4000 read both. So non-readers are 7000 - 4000 = 3000

Dhruv Tyagi - 5 years ago

that's a bitttt complicated, sorry.

mash religion - 3 years, 6 months ago

Brother this question is wrong if totall it it 5000 xtra person auto addedd

Tarun Jaiswal - 7 years ago

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Question is not wrong. Did you notice that there are some people who read both of the papers? That means, 1st paper read by x number of people and 2nd paper read by y number of people and there are some people who read both(and they are from x and y).

Shubham Gaikwad - 6 years, 12 months ago
Mahiuddin Rasel
Jun 8, 2014

Draw a Venn Diagram, then it's so easy.

Let A = 28000,B=23000. A & B common People are 4000, let C = 4000, so total people is total People = (A+B)-C.totalPeople = 51000-4000=47000.

We know that total people in town is 50000 so we have left 3000 to reach total people. So the answer is 3000.

Or you could do it the way I did it....... 28000 people that read the NanJing Morning News + the 23,000 people that read NanJing Evening News = 51000 ( try doing that in your head, really! It's easy!) 51000 - the 4000 that read both = 47000, there are 50000 people in the town, so, it's 50000 - 47000 = 3000, so 3000 read both newspapers! Technically, ours are the same though... But, good explaining! Thx!

mash religion - 3 years, 6 months ago

Nice answer

Ali Zulfaqar - 7 years ago

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You're right!

mash religion - 3 years, 6 months ago

From the Venn Diagram above, the number of people who read neither is

50000 19000 4000 24000 = 50000-19000-4000-24000= 3000 \boxed{3000}

That's how I did it! ( explained in great detail above) the only thing I didn't do is the Venn Diagram.

mash religion - 3 years, 6 months ago

28k + 23k = 51k 51k - 4k = 47k 50k-47k = 3k

:))

Ahmed Samy Rakha
Jun 7, 2014

People who read the first newspaper = 28000 People who read the second newspaper = 23000 Let people who read first only as 28000-x (in which x is the number of people out of the 28000 who read both) Let people who read second only as 23000-y (in which y is the number of people out of the 23000 who read both) So x+y=4000 By adding both we get the total number of people who read any of the two newspapers: 28000-x+23000-y Since x+y=4000 Therefore x= 4000-y By substituting: 28000-(4000-y)+23000-y 28000-4000+y+23000-y 28000-4000+23000=47000 Since total number of people in the city =50000 Therefore number of people who read neither = 50000-47000=3000

Just subtract 4000 from first and second newspaper readers and let the people who read nothing be x ,

19000 + 24000 + 4000 + x = 50000

=> 47000 + x = 50000

=> x = 3000

Rhishikesh Dongre - 7 years ago
Jeevith Gnana
Jun 7, 2014

50,000-4,000 is the number of people who don't read both news. The total number of people who read at least one type of news is (28,000+23,000)-4000. We subtract 4000 because that gets rid of the people who read both types of news. Now we are left with 47,000, which is the number of people who read either types of news, or both. So the people who read neither will be 50,0000 (total population) - 47,000 (The number of people who read at least one of the magazines.

I attacked this problem by using Venn Diagram.

Apply Inclusion-Exclusion Principle, i.e., 28000+23000-4000=47000. Then subtract 47000 to 50000 to get the number of people who neither read those newspapers.

Thus, the answer is 3000.

50000-(28000+23000-4000)=3000

Krishna Garg
Jun 6, 2014

Since 4000 did read both out of 50,000 ,so 46,000 did not read papers,Now, 22,000 ( 50,000-28,000)and 27,000 ( 50,000-23,000)did not read NanJing morning and Nanjing Evening news. Therefore 22,000 +27,000 =49,000 did not read papers and 49,000 -46,000 =3000 people read neighter Ans. K.K.GARG,India

n(A) = 28000. n(B) = 23000. n(A^B) = 4000 n(AUB) = n(A) + n(B) - n(A^B). n(AUB) = 28000 + 23000 - 4000. n(AUB) = 47000. No. Of people who read neither =Total - n(AUB) . =50000 - 47000 . = 3000.

yuvraj kamandar - 7 years ago

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