In a college of 300 students, every student reads 5 newspapers and every newspaper is read by 60 students. How many newspapers are there?
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Why can't this problem be true for when the number of newspaper would be 5
the question should have been more specific about number of publishers
If six papers r there then every paper can be read by 60 students and every one can read 5 papers
Why can't there be 5 newspapers??
The question is worded incorrectly for only one answer.
if 300 members bring 5 different papers then total no.of newspapers wii be 1500 then 25 will be wrong
!!!!!!!!!!!
got it now,,,thanks aswad
ok now i got the problem.......thank u
it is complexity and it 's real puzzle
NSEA 2013 question, word to word!
300*5=1500 1500/60=25
correct solution!!
Let no. of newspapers=N
No. of readings = 60N=300*5
N=25
incorrect question, asking for number of newspaper instead of publishers.
Firstly, we will find that how many students read one news paper so, 300÷60=5 We know that every student read 5 news papers 5×5=25 Answer is 25
This is the best solution.
No, one newspaper is read by 60 students according to the question. 60
Let n be the number of newspapers.
300 x 5=60 x n
1500=60n
n=1500/60 =25
Vividly, 300 times of 5 reads divided to 60 reads is 25. Actually, there must be 5 sets of different newspapers:
A B C D E
A B C D E
A B C D E
A B C D E
A B C D E
300 students divided into 5 groups with 60, 60, 60, 60 and 60. Each 60 take one A, one B, one C, one D and one E. Therefore, there are 5 x 5 of newspapers required which is 25 as total. Difficulty arise from coincidence of numbers made for conceptual confusion, I think.
Hello, I find your answer closest to mine so I comment it here. However, my answer is 5. So suppose we have 5 sets of newspapers: A B C D and E, each set published and dedicated to 60 students to read, wouldn't it be possible that sets B C D and E be given to those who read A? In this manner, there will be 5 sets of different newspapers for each student, each set read by 60 students. This is my first time to comment, and I'm just amused with the question. Thank you! :)
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Can't remember exactly, seems 5 not quoted as a choice. The 60 students who read A made the A read by 60 students. Similarly, B C D and E have also been read by others for 60 times. 'Every newspaper is read by 60 students' means no newspaper can be read for more than 60 times, which of course for reason of no availability, as mentioned in the question. Therefore, B C D and E once read by others cannot be read by the 60 students who read A. There must be other sets to be available to them. 300 students sharing only 5 newspapers is not logical unless they don't read them.
This is too simple. If a newspaper lasts for 60 reads we can just split the students in cohorts of 60 (300 / 60 = 5) and give each of 5 cohorts all 5 newspapers. 5 * 5 =25.
BTW the image says in Russian 'Read papers in Karelian' (a minority Finnish language spoken near St.Petersburg).
Each newspaper is read by 60 students.
Thus 300/60 = 5 one type of newspaper will be required
But every student read 5 different newspaper.
Thus number of newspaper required = 5*5=25
We can split the students into sets of 60, and the newspapers into sets of 5, each of 60 students can read all 5 papers, and then the set complies with the bounds given. Now we need simply scale up by multiplying the ratio of 60:5, and we get 25 papers for 300 students.
simple... one read 5 newspaper and 300 read 300*5=1500 agail 60 read same newspaper so 1500/60=25...
as every newspaper is read by 60 students,there should be 5 newspaper is needed for 300 students(300/60)...and as every students read 5 newspaper so exactly 25 is needed.(5.5)=25
Since every newspaper is read by 60 students, we distribute 1 newspaper to first 60 students, then 2nd newspaper to 60 students, so in dis way we require 5 set of newspapers. 2nd set of 5 newspapers is taken n distributed to 1st 60 students. in this way all 2nd set of 5 newspapers is distributed to 300 students. in this way, each student has read newspaper 2 times. So taking 3 more set of 5 newspapers, each student will read 5 newspapers. Hence 25 newspapers are required.
Answer: 300 students x 5 newspapers=1500 newspapers read 1500 newspapers ÷ 60 students = 25 newspaper
total newspaper read by 300 student=1500 1newspaper read by 60 student then newspaper read by 1 student=1/60 then,newspaper read by 1500 student=1500/6=25
ans. 25 solution : 300 X 5 / 60 = 25
Let x be the number of Newspaper.
60/300=5/x 60x=1500 x=1500/60 x=25 Therefore, the total number of newspaper is exactly 25.
300/60= #.newspapers read by all students *5(for each student) = 25 (total)
Reword the question: How many newspapers can 300 students read, if each can read 5 and each newspaper is read by 60 students? 300*5 = potentially 1500 newspapers. But that would be spread too thin for each to be read by 60 students. 1500/60 = 25 newspapers that can be read by 60 students each.
since 60students rteach one news pap-er and each student reads 5 news papers thus 300 students are covered by 5 X5 =25 news papers .Ans K.K.GARG,India
300 Hundred Stu. x every stud. Read Newsp is 05=1500= every news paper read by 60 student 1500 ÷60=25 =its easy
As there are 300 students in the college, whereby 60 students each read one of N newspapers, we get 300/60=N/5 (total students per students reading 1 paper is equal to total papers per number of papers read by 1 student)
300/60=N/5
N=(300/60)×5
N=5×5
N=25
300(5) = 1500, 1500/60 = 25
This is cool. This is where 'divided to' and 'divided by' sound differently.
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25
Of course the real puzzle here is figuring out the question. ; )
Which should read something like the following. Question: If in a college of 300 students, every student reads 5 newspapers and every newspaper is read by 60 students, what is the total number of newspapers.
Answer: 300 students x 5 newspapers=1500 newspapers 1500 newspapers ÷ 60 students = 25 newspaper publishers