Newton!

Classical Mechanics Level 2

Suppose there is a 40 kg 40 \text{ kg} box lying on the floor with the coefficient of static friction is equal to 0.5. External force applied on the box is 150 N 150\text{ N} . What is the net force on the box?

Take g = 10 m/s 2 g=10\text{ m/s}^2 .


The answer is 0.

Saraswati Sharma by Saraswati Sharma , 23, India

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1 solution

Saraswati Sharma
Nov 9, 2016

Static friction calculated static Frictional force = 200 N External force applied = 150 N According to Newton's Third Law .... Every Action has equal and opposite reaction.

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Nice problem :) . It is very basic concept checking problem :D

Md Zuhair - 4 years, 7 months ago

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Thanks. Glad u liked it :)

Saraswati Sharma - 4 years, 7 months ago

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