Newtonian mechanics

A cricket ball of mass 145 g is moving with a velocity of 14m/s and is being hit by a bat,so that the ball is turned back with a velocity of 22m/s.The force of blow acts on the ball for 0.015s. What is the average force exerted by the bat on the ball?

345N 315N 348N 390N 650N 148N 685N 683N

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2 solutions

Sarvesh Dubey
Jun 23, 2015

Since in this case the ball and bat act as action reaction pairs...we consider the bat as the reaction force... The ball hits the bat and exerts a force lets say F(1) and this the equal and opposite force will be F(2) This F(1)=F(2) THEREFORE m(1) a(1)=m(2) a(2) Since the mass is same...therefore a(1)=a(2) Therefore by using kinematics.... a(1)=14/(0.015-t) and a(2)=22/t Equate these two u will get t and then use this time t and find a(2) and replace it in F(2) And this the answer is 348 N Don't forget the mass is in grams convert first it to kg....

Sorry but if you see carefully you will notice that you have given the mass in kg, not grams.so the answer should be 348000

Shivam Saxena - 5 years, 11 months ago

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348N is the correct answer. Convert 145g into kg first because N is kgm/s^2

Kim Lehi Alterado - 5 years, 1 month ago
Jiahui Tan
May 8, 2019

F = m a = m ( v f v i ) t = 0.145 k g ( 14 m / s 22 m / s ) 0.015 s = 348 N F = ma = \frac{m(v_{f} - v_{i})}{t}= \frac{0.145kg(-14m/s - 22m/s)}{0.015s} = -348N

Had quite some struggle comprehending op’s original solution, so posting this one.

Jiahui Tan - 2 years, 1 month ago

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