Newton's Block !!!!!

What is the acceleration of a man of 40 k g 40kg plus the block of 10 k g 10kg system shown in the figure if the man applies a force of 30 N 30N on the string (the plane is fixed , smooth , horizontal). Also the string is horizontal.

Give your answer in m / s 2 m/s^{2} .


The answer is 1.2.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Ed Sirett
Sep 22, 2016

I solved this on the third attemp. Total mass of system is 40+10 = 50kg. So simply 30N/50kg = 0.6 m/s^2. Relative to the wider world. That wasn't it!

So is it a trick question? The plane is smooth and the man simply can't get the friction to apply 30N to the string. So try 0! No. That wasn't it.

Well the block is acc'ing at 0.6 m/s^2 left and the man 0.6 to the right so the block is accelerating RELATIVE to the man at 1.2 m/s^2 That's the "Right" answer.

1- How can the man accelerating to the right if the force in the string is to the left and there is no force to the right? 2- The question is not the acceleration of the box relative to the man but the acceleration of the system

AHMED KASSEM - 1 year, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...