4 , 1 5 , 4 0 , 8 5 , _ _
Find the next term in the sequence above.
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4 = ( 2 + 0 ) ⋅ ( 2 ) 1 5 = ( 2 + 1 ) ⋅ ( 2 + 3 ) 4 0 = ( 2 + 2 ) ⋅ ( 2 + 3 + 5 ) 8 5 = ( 2 + 3 ) ⋅ ( 2 + 3 + 5 + 7 ) 1 5 6 = ( 2 + 4 ) ⋅ ( 2 + 3 + 5 + 7 + 9 )
Can the next term be (2+4)(2+3+5+7+11)=168,because 2,3,5,7,11 are primes?
This can also be represented as n^3+n^2+n+1.
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4 = 1 3 + 1 2 + 1 + 1
1 5 = 2 3 + 2 2 + 2 + 1
4 0 = 3 3 + 3 2 + 3 + 1
8 5 = 4 3 + 4 2 + 4 + 1
a = 5 3 + 5 2 + 5 + 1 = 1 2 5 + 2 5 + 5 + 1 = 1 5 6