Let , where is a real number.
Let the sum of all the values can take be . Find .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Pretty easy. The integral is straightforward and evaluates to 2 π − tan − 1 ( b n ) . Now since b ∈ R so let's take three simple cases:
CASE I: b < 0 Now applying limit we get I = π
CASE II: b = 0 This gives I = 2 π
CASE III: b > 0 This gives I = 0
Now summing them up we have ⌊ A ⌋ = ⌊ 2 3 π ⌋ = 4 .