An algebra problem by Akshay Sharma
x n + 1 = 1 + x n + x n 2 x n + x n 2 ; x 1 = 2 1 If { x n } is a sequence of numbers such that they satisfy the recurrence relation above, then determine: x 1 + 1 1 + x 2 + 1 1 + x 3 + 1 1 + . . . . . . x 2 0 1 2 + 1 1 + x 2 0 1 3 1
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The answer is 2014.
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