Nickels and Quarters

Algebra Level 1

Andrew and Betsy have some nickels (5 cents) and quarters (25 cents).
Betsy has exactly 45 cents.
Andrew has half as many nickels and twice as many quarters as Betsy has.

How much money does Andrew have?

70 cents 60 cents 90 cents 80 cents

Chung Kevin by Chung Kevin , 45, Australia

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2 solutions

Barr Shiv
Dec 11, 2018

num of nickels of andrew:x
num of quarters betsy:y
therefore: 2x×5+y×25=45
2x+5y=9
y=1 x=2
therefore: 2×5+2×25=60

1 Helpful 1 Interesting 0 Brilliant 0 Confused
Hitesh Behera
Nov 22, 2019

Let X be amount Andrew has.

Say they have N nickels & Q quarters. So from given case of Betsy, we have the equation as: 5N+25Q=45 cents. Here it can be seen, N=4 & Q=1

And from Andrew's case we get the equation as: [(5N)÷2]+[(25Q)×2]=X

By the substituting the values of N&Q we have; [(5×4)÷2]+[(25×1)×2] =10+50 = 60 cents

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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