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Without using a calculator, find the value of log 10 1024 \log _{ 10 }{ 1024 } , given that l n ( 2 ) = 0.69315 ln(2)=0.69315 and l n ( 2.5 ) = 0.91629 ln(2.5)=0.91629


The answer is 3.0103.

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1 solution

Formulae used in the following solution

  • log a b = log c b log c a \log_{a}{b} = \frac{\log_{c}{b}}{\log_{c}{a}}

  • log a b c = c × log a b \log_{a}{b^c}=c \times \log_{a}{b}

  • log a ( b × c ) = log a b + log a c \log_{a}{(b\times c)}=\log_{a}{b}+\log_{a}{c}

log 10 1024 = 10 × log e 2 log e 10 = 10 × log e 2 log e 2.5 + 2 × log e 2 \log_{10}{1024} = 10 \times \frac{\log_{e}{2}}{\log_{e}{10}}=10 \times \frac{\log_{e}{2}}{\log_{e}{2.5 + 2\times \log_{e}{2}}}

Which can be evaluated using given values

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