True or False?
5 2 4 7 3 1 5 6 + 9 8 1 1 3 = 1 0 5 8 2 3 8 1 7
No calculator needed. Use Fermat's Last Theorem .
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Fermat's last theorem says, that no x n + y n = z n has no positive integral (integer) solutions for n > 2 .
Rearranging:
4 7 3 1 5 6 + 9 8 1 1 3 = 1 0 5 8 2 3 8 1 7 5 2
Rewriting:
( 4 7 3 1 2 ) 1 3 + 9 8 1 1 3 = ( 1 0 5 8 2 3 8 1 7 4 ) 1 3
Due to Fermat's theorem, it must have no solutions ( n = 1 3 ).
Checking with Calculator (don't do this, just trying to show)
4 7 3 1 5 6 + 9 8 1 1 3 =
1898182455987008946396006363347308090945891508259974310597456828126172089112739214102767043783335566247400837579465612442872991162298052157315387100663665430703590466947887678679235884216295902469587608194039586910361116996504612190227718265817732730585408218274194030911655001269442358944233592451831877370746586205453731339911485478915302078897214317241051804145723391462653591708006051388370018769028511822619781702
1 0 5 8 2 3 8 1 7 5 2 =
1898182455987008946396006363347308090945891508259974310597456828126172089112739214102767043783335566247400837579465612442872991162298052157315387100663665430703590466947887678679235884216295902469587608194039586910361116996504612190227718265817732730585408218274194030911655001269442358944233592451831877370746586205453731339911485478915302078897214317241051804145723391462653590928719653394306258535732918833303945761
Your calculator could round this and call it equal, even though it is not.
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Consider ( 4 7 3 1 2 ) 1 3 + 9 8 1 1 3 = ( 1 0 5 8 2 3 8 1 7 4 ) 1 3
⇒ 5 2 4 7 3 1 5 6 + 9 8 1 1 3 = 1 0 5 8 2 3 8 1 7