An algebra problem by Interliser 727

Algebra Level 2

Dean wants 200 ribbons of length 110 centimeters for a party. However, the ribbons are sold at 25 meters per tape. How many tapes of ribbon will Dean needs?


The answer is 10.

Interliser 727 by Interliser 727 , 22, Malaysia

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1 solution

Interliser 727
Apr 30, 2018

110 c m = 1.1 m 110cm=1.1m

25 m / t a p e 1.1 m / r i b b o n \frac{25m/tape}{1.1m/ribbon} = = 22 + 8 11 r i b b o n 22+\frac{8}{11}ribbon

So each tape can make 22 ribbons! So,

200 r i b b o n s 22 r i b b o n s / t a p e \frac{200 ribbons}{22 ribbons/tape} = 9 + 1 11 =9+\frac{1}{11} t a p e s tapes

As 9 + 1 11 9+\frac{1}{11} has excess, we need one more tape so it is 10 \boxed{10}

2 Helpful 0 Interesting 0 Brilliant 0 Confused

It should be clear, in some way, that ribbons cannot be taped or otherwise attached to each other to make longer stretches. But I guess it will do the way it is.

Marta Reece - 3 years, 1 month ago

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So sorry a typo occured! Thanks for pointing out.

Interliser 727 - 3 years, 1 month ago

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