The figure above shows the graph of an ellipse having a horizontal semi-major axis of 2 units, and a vertical semi-minor axis of 1 unit. That is, its equation is
4 x 2 + y 2 = 1
Two perpendicular lines (shown in red) are at 45 degrees with the x -axis, and pass through the origin. They segment the ellipse into 4 segments. From symmetry, there are only two distinct values of the area of a segment. Find the ratio of the area of the larger segment to the area of the smaller segment.
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You can easily integrate and find the result. The integration requires trigonometric substitution only.
But, there's another way to solve it. We'll look for axis transformation which will change our ellipse into a circle.
Let, X = 2 x Then, our ellipse is an circle in X − y axes. And, the lines y = ± x change to y = ± 2 X . Now, you can find the angle which the line y = 2 X makes with X-axis. Therefore, the first quadrant is divided into t a n − 1 2 and t a n − 1 2 1 . These angles are proportional to the divided area. So, the required ratio is t a n − 1 0 . 5 t a n − 1 2 ≈ 2 . 3 8 8
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