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The diagonal of a rectangular field ABCD is (P+9)m and the sides are (P+7)m and P m. Find the value of P.


The answer is 8.

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1 solution

Victor Loh
Jan 4, 2014

Using Pythagoras Theorem,

P 2 + ( P + 7 ) 2 = ( P + 9 ) 2 P^{2}+(P+7)^{2}=(P+9)^{2}

P 2 + P 2 + 2 ( 7 P ) + 7 2 = P 2 + 2 ( 9 P ) + 9 2 P^{2}+P^{2}+2(7P) + 7^{2} = P^{2} + 2(9P) + 9^{2}

2 P 2 + 14 P + 49 = P 2 + 18 P + 81 2P^{2} + 14P + 49 = P^{2} +18P + 81

P 2 4 P 32 = 0 P^{2} - 4P - 32 = 0

( P + 4 ) ( P 8 ) = 0 (P+4)(P-8)=0

As P 0 P\geq 0 , P = 8 \boxed{P=8} .

it is good sum

sujit kumar - 7 years, 3 months ago

Even i did d same..

PRABHA Y N - 7 years, 2 months ago

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