No. of digits?
Number Theory
Level
1
Find the total number of digits in the decimal expansion of
2003
2002
2000
2001
2004
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1 solution
(2^2006)(5^2000) = (2^6)(2^2000)(5^2000) = (2^6)(10^2000) = 64(10^2000) = 6400000.......(2000 trailing zeros) Result : 2 digits from "64" + 2000 trailing zeros = 2002 digits in total