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Algebra Level 2

If

sinA + sinB + sinC = 3

Find the value of cosA + cosB + cosC


The answer is 0.

Anshuman Shreshth by Anshuman Shreshth , 21, India

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4 solutions

differentiating

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Abhi Kumbale
Nov 20, 2016

Boundary value problem.

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Fox To-ong
Feb 6, 2015

for the maximum value of A is 90, thus cos of 90 way to sum it up = zero

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Kshitij Gajapure
Jan 15, 2015

since sinA+sinB+sinC = 3 sinA = sinB = sinC = 1 ,therefore A=B=C=90° ,so cosA = cosB = cosC = 0 ,thus cosA+cosB+cosC = 0

0 Helpful 0 Interesting 0 Brilliant 0 Confused

Nice, but A , B , C A,B,C are in radians, and they need not be π 2 \dfrac{\pi}{2} . There are other points where the sine is unity.

Satvik Golechha - 6 years, 4 months ago

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sorry A=B=C=π/2+2nπ . And while solving such examples we generally consider them in [0,2π]

Kshitij Gajapure - 6 years, 4 months ago

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