Noise Pollution Is Harmful 3!

Classical Mechanics Level 2

Find apparant frequency heard by observer 1 + apparant frequency heard by observer 2 at the moment when the sources have covered a distance of 75 m.

Details And Assumptions

• Take speed of sound as 300m/s .

• Take value of g as 10 m/s²

• Observer 1 cannot hear sound heard by observer 2 and vice versa

• Assume that sound is passing through air all time

• Enter answer to 2 decimal places with proper estimation

• Enter answer in Hertz(Hz)


The answer is 20370.37.

Aryan Sanghi by Aryan Sanghi , 16, India

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1 solution

Acceleration of the 16 16 kg. source is 6 6 m/s 2 ^2 downwards, of the 4 4 kg. source is 6 6 m/s 2 ^2 upwards, of the 7.5 7.5 kg. observer is 10 10 m/s 2 ^2 downwards and of the 2.5 2.5 kg. observer is 10 10 m/s 2 ^2 upwards. After covering a distance of 75 75 m., the speeds of the sources are 30 30 m/s each, and the time taken to cover this distance is 5 5 sec. In this time, the speeds attained by the observers are 50 50 m/s. each. So the apperant frequency heard by the first observer is 10000 × 300 + 50 300 − 30 ≈ 12962.963 10000\times \dfrac{300+50}{300-30}\approx 12962.963 Hz, and by the second observer is 10000 × 300 − 50 300 + 30 ≈ 7575.757 10000\times \dfrac{300-50}{300+30}\approx 7575.757 Hz. Hence the required sum is 20538.721 \boxed {20538.721} Hz.

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