Non-elementry closed form

Calculus Level pending

If the integral 0 1 2 tanh 1 x x 5 d x = 5 b c a ( ln d c e 2 F 1 ( p q , 1 , r q , 1 s ) ) \int_0^{\frac{1}{2}}\dfrac{\tanh^{-1} x}{\sqrt[5]{x}}dx =\dfrac{5}{\sqrt[a]{b^c}}\left(\ln d-\dfrac{c}{e} {}_2F_1\left(\frac{p}{q},1,\frac{r}{q},\frac{1}{s}\right)\right) where all the unknowns are positive integers with a , b , d a,b,d are primes, then find the sum of all positive integers.


The original problem belongs to Sir Srinivasa Raghava where he proposed to evaluate the integral in closed form, ie; 0 1 2 tanh 1 x x 5 d x \int_0^{\frac{1}{2}}\frac{\tanh^{-1}x}{\sqrt[5]{x}} dx


Notation: 2 F 1 ( a , b ; c ; z ) {}_2F_1(a,b;c;z) is Gaussian hypergeometric function.


The answer is 81.

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1 solution

Naren Bhandari
May 8, 2020

Lazy to do latex work :D so I'm just sharing the closed form that I found. 0 1 2 tanh 1 x x 5 d x = 5 2 19 5 ( ln 3 5 9 2 F 1 ( 9 10 , 1 ; 19 10 , 1 4 ) ) = 0.166555580 \int_0^{\frac{1}{2}}\dfrac{\tanh^{-1} x}{\sqrt[5]{x}}dx =\dfrac{5}{\sqrt[5]{2^{19}}}\left(\ln 3-\dfrac{5}{9} {}_2F_1\left(\frac{9}{10},1;\frac{19}{10},\frac{1}{4}\right)\right)=0.166555580\cdots Note that the integral can be represented in the form two separate sums that are convergent one of those is trival to evaluate the next involves the hypergeometric expression.

Matlab brought 0.166555580713847 as the required answer.

Quadry Abiodun Omolesho - 1 year, 1 month ago

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