What is the Ammeter reading (in amperes)?
Given -
Area of cross section of wire =
Resistance across AB (Internal Resistance of battery ) =
Resistance of ammeter =
E.M.F. of battery =
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There are six segments. Use the formula R = A ρ L . Then add 3 5 Ω of additional resistance for a total of 5 0 Ω . The current through the ammeter is 5 0 Ω 5 0 0 V = 1 0 A . I used a spreadsheet to do the calculations.