If the probability that a number chosen b/w 1 and 1000(both inclusive) is not a perfect cube given that it doesn't has odd number of divisors be represented by where (a,b)=1 ,find the absolute value of (a-b) ?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
No explanations have been posted yet. Check back later!