Not an odd no. with no evens...
If the probability that a number chosen b/w 1 and 1000(both inclusive) is not an odd number given that it has even number of divisors be represented by where (a,b)=1 ,what is the absolute value of ?
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1 solution
A number has odd number of divisors if it is a perfect square.
From 1-1000, 31 perfect squares are there (1², 2²,......31²=961)
So remaining are 969 numbers out of which (500-16) are odd and (500-15) are even.
Hence required probability (not odd number) = 485/969
a=485, b=969
|a-b|= 484 = a-1