Where should I look at first?

$\angle QRP = \angle QPS \Rightarrow \angle POQ = \large \color{#20A900}{\boxed{50°}}$

$\large \text{The diagram above is drawn to scale}$

$\Large \angle {OPT} \space \text{is obviously}\space 90^\circ \text{ because it's tangent to a circle}$

$\Large \angle { TOP} =\Large 180^\circ - \measuredangle{OTP} - \measuredangle{OPT} \\ \Large = 180^\circ - 25^\circ - 90^\circ \\ \Large = 65^\circ$

$\Large \text{ Since }PQ\text{ is parallel to} \space CD \text{, so we can conclude that} \\ \Large \measuredangle {TOP} = \angle {OPQ} \\ \Large 65^\circ = \measuredangle {OPQ}$

$\Large \text{Since } OP\text{ and} \space OQ \text{ is the same length, we can conclude that }\\ \Large \measuredangle {OPQ} = \angle{ OQP} \\ \Large 65^\circ = \measuredangle {OQP}$

$\Large \text{Finally,}\\ \Large \angle {POQ} = 180^\circ - \measuredangle{OPQ} - \measuredangle{OQP} \\ \Large = 180^\circ - 65^\circ - 65^\circ \\ \Large =180^\circ - 130^\circ \\ \Large = \Huge \color{#20A900}{\clubsuit} \color{#D61F06}{\spadesuit} \space \color{#D61F06}{50^\circ} \color{#20A900}{\clubsuit} \color{#D61F06}{\spadesuit}$

$\large \text{The Spadesuit(} \spadesuit \text{)and the Clubsuit(} \clubsuit \text{) are just for the decoration.}\\ \large \text{Want more ? :) }$