Not as simple as it appears

Calculus Level 5

{ d v d t = 4 v 5 w d w d t = 2 v 3 w \large \begin{cases} \dfrac{dv}{dt} = 4v - 5w \\ \dfrac{dw}{dt} = 2v - 3w \end{cases}

Solve the system of differential equations above. Given that v ( 0 ) = 8 v(0) = 8 and w ( 0 ) = 5 w(0) = 5 , evaluate v ( 1 ) w ( 1 ) \left \lfloor v(1) - w(1) \right \rfloor


The answer is 22.

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2 solutions

Fiki Akbar
Feb 27, 2015

By substracting the two original equations, we have d d t ( v w ) = 2 ( v w ) \frac{d}{dt} (v-w) = 2(v-w)

Integrating the equation, we get the general solution ( v w ) ( t ) = C e 2 t (v-w)(t) = C e^{2t}

Since ( v w ) ( 0 ) = 3 (v-w)(0)=3 , then ( v w ) ( t ) = 3 e 2 t (v-w)(t) = 3e^{2t}

For t = 1 t=1 , we have ( v w ) ( 1 ) = 3 e 2 = 22.167 (v-w)(1) = 3e^{2} = 22.167

Mayank Singh
Oct 21, 2015

Well, the title should be "It's simpler than it appears"

Absolutely correct

Prithwish Mukherjee - 2 years ago

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