There are two half ellipse in the rectangle as given above.
What could be perimeter of the above shape..?? (approx)
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First we have to find perimeter of ellipse and there are number of formulas by which we can do so. Hence I have put "Approx" word.
To find perimeter of ellipse we first have to find h .
h = ( a + b ) 2 ( a − b ) 2
h = ( 2 2 + 9 . 5 ) 2 ( 2 2 − 9 . 5 ) 2
= 0.15747
p = π ( a + b ) ∑ n = 0 ∞ ( n 0 . 5 ) 2 h n
Simplifying the same we get,
p = π ( a + b ) ( 1 + 4 1 h + 6 4 1 h 2 + 2 5 6 1 h 3 + . . . . )
put a = 22
put b = 9.5
put h = 0.15747
Final answer of perimeter of ellipse will be 102.8575
We have two half ellipse hence its total perimeter will be 1/2 (102.8575 * 2 ellipse) = 102.8575.
Now add remaining portion of the shape which is 35 + 35 + 2 + 2 = 74.
And final perimeter of the shape will be 102.8575 + 74 = 176.8575.
May take a look at external source here .
The perimeter of the oval would be extremely dependent on the curvature of the oval, i.e. the extent to which it is curved. Your options are quite close together.
Did you want for it to be an ellipse? That is a different shape from an oval.
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Yess it is ellipse.... i made changes accordingly....
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First we have to find perimeter of ellipse and there are number of formulas by which we can do so. Hence I have put "Approx" word. To find perimeter of ellipse we first have to find . = 0.15747 Simplifying the same we get, put a = 22 put b = 9.5 put h = 0.15747 Final answer of perimeter of ellipse will be 102.8575 We have two half ellipse hence its total perimeter will be 1/2 (102.8575 * 2 ellipse) = 102.8575. Now add remaining portion of the shape which is 35 + 35 + 2 + 2 = 74. And final perimeter of the shape will be 102.8575 + 74 = 176.8575.