Not that radically difficult

Algebra Level pending

n = p ( p + 1 ) + p ( p + 1 ) + . . . p ( p 1 ) p ( p 1 ) . . . \large n = \sqrt{p(p+1) + \sqrt{p(p+1) + ...}} - \sqrt{p(p-1) - \sqrt{p(p-1) - ...}}

Evaluate n n .

Details and Assumptions :

  • p p is greater than or equal to 1 1 .

  • " . . . ... " means that the terms are reiterated and nested.

0 0 2 p 2p 1 1 p p 2 2

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1 solution

Louie Dy
Jul 7, 2016

This problem is simpler than how it appears.

Let's focus on each term individually.

Let x = p ( p + 1 ) + p ( p + 1 ) + . . . x = \sqrt{p(p+1) + \sqrt{p(p+1) + ...}} . This can be represented as x = p ( p + 1 ) + x x = \sqrt{p(p+1) + x} .

Solving for x leads to x 2 = p ( p + 1 ) + x x^2 = p(p+1) + x , which leads to p + 1 p+1 as the only valid solution.

Let y = p ( p 1 ) p ( p 1 ) . . . y = \sqrt{p(p-1) - \sqrt{p(p-1) - ...}} . This can be represented as y = p ( p 1 ) y y = \sqrt{p(p-1) - y} .

Solving for y leads to y 2 = p ( p 1 ) y y^2 = p(p-1) - y , which leads to p 1 p-1 as the only valid solution.

Therefore the answer is 2 \boxed{2} .

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