Astronauts Did This To The Moon. Scientists Are Thankful For It.

• Distance travelled by the light = d = 385000+385000 = 770000 km

• Speed of light = v = 300000 km/s

• So time taken = d/v = 770000/300000 seconds = 2.566667 seconds

we can use the formula

t= $\frac {s}{v}$

which t is time s is distance and v is velocity based from the problem , the distance is 385,000 km or 385,000,000 m and the velocity are $3 \times\ 10^{8}$ m/s or 300,000,000 m/s to obtain the time, we will use the formula above , and thus we obtain

$\frac {385,000,000}{300,000,000}$ = 1.283 and because it is still the time needed by the laser to reach the moon to know the time it needed back and forth is

$1.283 \times 2$ = 2.566 and with decimal approach we will obtain $\boxed{2.570}$

The distance of moon from earth is 385000 km or 385000000 metre. The speed of the laser pulse= speed of light = 3 x 10^8 metre/s. So, one way time= 385000000/ 300000000 = 1.283 and two way time = 2.566 seconds or 2.57 seconds.

Total distance=385,000 * 2=770000km=770000000m=7.7 * 10^8 Time=Distance/speed=7.7 * 10^8/3*10^8 =7.7/3=2.566666666... =2.57

$s=\frac{v \times t}{2}$

$t=\frac{2s}{v}$

$t=\frac{2 \times 385,000,000}{300,000,000}$

$t=\boxed{2.566667}$

Distance travelled by the laser light= 385000 x 2 (Because the light has to travel to the moon and come back) speed of the light = 3 x 10^8 m/s time = distance / velocity So the answer is 2.566 (approx) seconds

VELOCITY=DISTANCE/TIME SO, TIME=DISTANCE/VELOCITY SO t=2 385000/3 1O^8 (2 IS MULTIPLIED BECAUSE OF THE LASER PULSE RETURN BACK TO EARTH) t=2.5666667

what will happen if moon goes on forever.

time taken in seconds for a short laser pulse to bounce off the moon and come back=speed of laser pulse total distance travelled by the short laser =2 (385000*1000)/300000000 =2.567

distance from the earth to moon is 385000km we should covert it in meters we get 385000000m ,speed=300000000m/s , using time formula t=d/s=385000000/300000000=1.28sec. now the time of ray coming back to earth 2*1.28=2.57sec

velocity of light =3E10 distance of moon from earth =385000km =385E6 m time=distance/speed =385E6/3E10 =1.283 s therefore distance from earth to moon and return =1.283 s * 2=2.56

Distance=Speed Time Time = Distance/Speed = 385000 km *2/3 10^8 (since the laser will have to come back after reflection the distance traveled will be two times) =385000000 2 m s/3 10^8 m =2.57 sec

Total distance = 385000 km x 2; or 385000000 meters x 2 = 7.7E8 meters; Velocity of light = 3E8 m/s; As we know that; speed (v) = distance(d)/time(t); or time (t) = distance(d)/speed(v) time(t )= 7.7E8/3E8 = 2.57 seconds

Actually the universally accepted value of speed of light is 3 lac kilometers per seond. By applying the unitry method if found that it takes almost 1.28 sec for a pulse of light to reach the moon. If the minute variation in distance due to moving away of moon is neglected then the time taken by light to reach back the earth is also 1.28 sec. So the double of 1.28 is the time in seconds taken by the pulse of light in this experiment

• Net Distance to be covered by the Laser Light is,
  2 times the total Distance Between Earth And Moon i.e, $2 \times 385*10^{6}$ m.
  
• Speed of Light = $3 \times 10^{8}$ m/sec.
• as time = Distance/velocity
• therefore, time taken by Laser = $2 \times 385*10^{6}$ / $3 \times 10^{8}$ = 2.567

t = (S+S)/v = 2S/v = 2(385 x 10^6)/(3 x 10^8) = 2.5666666666666666666666.. seconds

t= twice the distance/ velocity

the distance is 385,000 km, making it up to 385,000,000 meters. since the laser needs to be bounced back to the earth, it makes the distance doubled up to 770,000,000 m.

distance (d) = 770,000,000 m

speed (s) = 3 x 10^8 m/s = 300,000,000 m/s

time (t) = ?

t = d/s = (770,000,000 m) / (300,000,000 m/s) = 2.56666666...., 2.567 or 2.57 seconds

It will be 2x(distance between moon and earth)/(speed of light)=2.5666 seconds

t = 2s/v ,...t=2(385000000 m)/300000000 m/s = 2.567 s

It's two times the time taken for the laser pulse to reach the moon which is (distance between moon and earth/speed of the pulse).

total distance travelled ba pulse = 385000 *2 km and speed of the pulse = 3E8 m/s so time= distance/speed

Light can travel 300,000 km/s.

Moon is away by 385,000 km.

Distance to be traveled by LASER to return to the Earth = 385,000 x 2 = 770,000 km

Therefore total traveling time by LASER light to a distance of 770,000 km is = 770,000/300,000 = 2.567

Velocity = displacement / time .. Therefore time taken for the 1-way trip is 385,000/3X10*5 = 1.28 seconds Therefore time taken for the entire trip is 2X 1.28 =2.56 seconds

Since speed=distance/time, time=distance/speed. Distance from earth to moon=385000000m. Therefore if the laser pulse start from earth to moon and back to earth again, time taken=2x385000000/300000000=2.566s

The solution is simple. We just use the formula ----------> Time = Distance/speed

Distance from the earth to the moon in metres = 385000000 m Time = 3*10^8 seconds = 300000000 s

Time = 385000000/300000000 = 1.28333333333 seconds = Time taken for beam to reach the moon

The question wants us to find the time taken for the beam to reach the moon and return to earth ------------------> 1.28333333333 * 2 = 2.56666666667 seconds = Answer

Let the distance between the earth and the moon be d The laser pulse goes and comes back, thus covering a total of 2d Let the speed of light be c

Time taken by light = 2d/c

Substituting d by 385000 km and c by 300000 kms^-1,

we get, t= 2.5667

r=d/t but in this problem we need to find for time(t) so

t=d/r

d= 385000 x 2 * double the distance since the laser pulse will do a sort of a *round-trip as it bounces off the mirror back to the Earth**

d=770000km

r= 3 x 10^8 m/s = 300000000 m/s note that the given unit for d is km so convert this to km

r= 3 x 10^5= 300000 km/s

Finally:

t= d / r

t=770000 km / 300000km/s

t= 2.57 s