Notebooks

Algebra Level 2

Rodrigo was to a stationary store and bought three notebooks. These notebooks were in sale. If you buy one notebook, the second and the third notebooks that you buy, will have 20% and 40% off, respectively.

In the next day, Gustavo was to the same stationary store and bought three notebooks too, but these notebooks weren't in sale anymore.

In percentage, how much Rodrigo paid unless than Gustavo?

Note: Rodrigo and Gustavo brought the same kind of notebooks.

Problem Source: OBMEP 2014

25% 30% 20% 28%

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Asim Das
Dec 18, 2014

Take the initial amount to be $100, therefore Rodrigo's, total expenditure was $240 and Gustavo's total expenditure was $300.

- To find out how much less % of money Rodrigo spent than Gustavo

JUST DO THIS :-

Dude $100 is too much for a book XD

Mehul Arora - 6 years, 5 months ago
Jack Rawlin
Dec 24, 2014

Let £ = £ = Price of notebook , a = a = Answer (%)

The first notebook bought by Rodrigo ( r r ) cost 100 100 % of the price, the second one cost ( 100 20 ) (100 - 20) % and the last cost ( 100 40 ) (100 - 40) % so adding these together gives

100 + ( 100 20 ) + ( 100 40 ) = 240 100 + (100 - 20) + (100 - 40) = 240

(That's 240 240 % of £ £ ). This can also be written as 2.4 £ 2.4£

Let r = 2.4 £ r = 2.4£

All three notebooks bought by Gustavo ( g g ) are the full price so ( 3 100 3 \cdot 100 % )

100 3 = 300 100 \cdot 3 = 300

(As with before this is 300 300 % of £ £ ). This can also be written as 3 £

Let g = 3 £ g = 3£

Next we find what a a equals by using the following formula

a = ( 1 r g ) 100 a = (1 - \frac {r}{g}) \cdot 100

( r g 100 \frac {r}{g} \cdot 100 is what percentage r r is of g g ) Since we know what r r and g g equal we can sub the values in

a = ( 1 2.4 £ 3 £ ) 100 a = (1 - \frac {2.4£}{3£}) \cdot 100

The £ £ s cancel out leaving

a = ( 1 2.4 3 ) 100 a = (1 - \frac {2.4}{3}) \cdot 100

Simplifying the brackets gives us

a = 0.6 3 100 a = \frac {0.6}{3} \cdot 100

If we then make the fractions denominator equal to 1 1 we get

a = 0.2 1 100 a = \frac {0.2}{1} \cdot 100

This becomes

a = 0.2 100 a = 0.2 \cdot 100

Which means that a = 20 a = 20

So the answer is 20 20 % less

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...