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1 solution
We have to find ( 1 0 0 + 7 ) 1 2 1 ( m o d 1 0 5 ) ≡ ( 0 1 2 1 ) 1 0 0 1 2 1 . 1 + ( 1 1 2 1 ) 1 0 0 1 2 0 . 7 + ⋯ + ( 1 1 9 1 2 1 ) 1 0 0 2 . 7 1 1 9 + ( 1 2 0 1 2 1 ) 1 0 0 . 7 1 2 0 + ( 1 2 1 1 2 1 ) 7 1 2 1 ( m o d 1 0 5 ) ≡ ( 1 2 1 . 1 0 0 . 7 1 2 0 + 7 1 2 1 ) = 7 1 2 0 ( 1 2 1 1 0 7 ) ( m o d 1 0 5 ) Then i used python to solve :P
look here
so 7 1 2 0 . ( 1 2 1 1 0 7 ) ( m o d 1 0 5 ) = 1 6 1 0 7 , therefore sum of digits is 1 5
Looking forward to do it without using computer help. Please do help :)