NOVAD-26 Virus

We are currently in March 2026. Over the past two months, a deadly virus, known by the name NOVAD-26, has been spreading around the world. Experts estimate the epidemic already infected around 800,000 humans globally. The fatality rate of the disease is about 2%. A new and innovative diagnostic testing is now used to quickly identify infected people. The test will correctly identify 99% of the people who have the virus, and only incorrectly identify 1% of the people who don’t have the virus. You are traveling for a vacation somewhere in Europe. Upon arrival to the airport you are being randomly selected to be tested for NOVAD-26 infection. Unfortunately for you, the test result is POSITIVE . What are the chances that you will die from the disease?

Assumption: world population is 8X10^9.


The answer is 0.000196.

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1 solution

Oded Barash
Feb 17, 2020

The test is 99% sensitive and 99% specific. That is, the test will produce 99% true positive results for infected humans, and 99% true negative results for non-infected humans.

Also, it is known that the number of infected humans is 8∙10^5.
Let us denote the following events:

I I - Infected

¬ I \lnot I - Not infected

T T - Positive test

¬ T \lnot T - Negative test

D D - Died

World population today is approximately 8 1 0 9 8\cdot 10^9 .

We can use this fact to estimate the prior probability for a human to be infected as follows:

P ( I ) = 8 1 0 5 8 1 0 9 = 0.0001 P(I)=\frac{8\cdot 10^5}{8\cdot 10^9}=0.0001

Now we can find the probability to be infected given that the test gave positive result using Baye’s theorem as follows:

P ( I | T ) = P ( T | I ) P ( I ) P ( T ) P\left(I\middle| T\right)=\frac{P\left(T\middle| I\right)\cdot P\left(I\right)}{P\left(T\right)}

= P ( T | I ) P ( I ) P ( T | I ) P ( I ) + P ( T | ¬ I ) P ( ¬ I ) =\ \frac{P\left(T\middle| I\right)\cdot P\left(I\right)}{P\left(T\middle| I\right)\cdot P\left(I\right)+P\left(T\middle|\lnot I\right)\cdot P\left(\lnot I\right)}

= 0.99 0.0001 0.99 0.0001 + 0.01 0.9999 0.0098 =\frac{0.99\cdot 0.0001}{0.99\cdot 0.0001+0.01\cdot 0.9999}\cong0.0098

The probability to die is than,

P ( D | I ) P ( I T ) = 0.02 0.0098 = 0.000196 P\left(D\middle| I\right)\cdot P(I|T)=0.02\cdot0.0098=0.000196

So even though the test gave a positive result, the chances for you to be infected are less than 1% and the chances that you will die by the virus are less than 0.02%.

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