Nth multiple of 4

The answer is 11 . This code iterates through integers i , and uses n to keep track of how many multiples of 4 we find. Once n == 11, the loop exits, and i contains the 11th multiple of 4. The function then returns i .

# python code start
def calc_nth_multiple_of_4():
    i = 0
    n = 0  # keeps track of how many multiples of 4 we've encountered
    while (n < 11):
        i += 1 

        # if i is a multiple of 4
        if (i % 4 == 0): 
            # increment n. i is the nth multiple of 4.
            n += 1
    return i