nth term of a series

The sequence here is just $\sum _{ n=1 }^{ 20 }{ \frac { 1 }{ 2n-1 } }$

So, when you plug 20 into the series, you get $1/39$

$\frac{1}{2n-1}$ Each term follows the above formula for next term.

$\frac{1}{2×20-1}{\implies}{\frac{1}{39}}$

Hence the answer is $\color{#3D99F6}{\boxed{\frac{1}{39}}}$