NTSE math

Let 2014 = x ; (x^2 - x - 6)(x+1)(x^2+x-6) / (x+2)(x+3)(x-3)(x-2); Factor (x^2 - x - 6) & (x^2+x-6); You will get (x-3)(x+2) & (x+3)(x-2) respectively; Everything can be then divided out, except (x+1) ; Put 2014 back into the brackets ; (2014+1) = 2015.//

let 2014 = a; now 2014 x 2014 - 2020 = 2014 x 2014 - 2014 - 6= a x a - a - 6 = a x a - 3a + 2a -6 = (a - 3)(a + 2) = (2011)( 2016); now 2014 x 2014 + 2008 = 2014 x 2014 +2014 - 6 = a x a + a - 6 = a x a + 3a -2a-6 = (a+3)(a-2)=(2012)(2017); now (2014 x 2014 - 2020 )(2015)( 2014 x 2014 + 2008) / (2016)(2017)(2011)(2012) = (2012)(2011)(2017)(2016)(2015)/ (2017)(2011)(2012)(2016) = 2015